102. As the conductor passes through 90, the sine function is

101. 99.98

θ (zero)

1.000; therefore, instantaneous voltage (e) equals Emax

(100 volts).

is NEVER greater than 1,000 (found at exactly 90. In order to

The sine function of

solve for instantaneous voltages in a conductor rotating through the second, third, and

in the second quadrant (90 to 180), subtract the angle rotated (in degrees) from 180.

In the third quadrant (180 to 270), subtract 180 from the angle rotated.

In the fourth quadrant (270 to 360), subtract the angle rotated from 360.

IT MUST BE NOTED:

Instantaneous values from 0 to 180 are on

the +Y axis and are positive.

Instantaneous values from 180 to 360 are on the -Y axis and are negative.