1.5 micro-
54.
Solve the problem below:
coulombs
Q = 525 coulomb
(Q = CE)
C = .025 f
E=
volts.
210
55.
Indicate, on the schematic drawing, the direction of the charging current
and the polarity of the charge on the capacitor.
56.
Solve the problem below:
C = .025 f
E = 40 volts
Q=
1 micro-
57.
Solve for Eapp.
coulomb
C = .02f
(Q = CE)
Q = 10.4 micro-coulombs
Eapp =
volts
1-18
IT0351
Previous Page
